5/7x^2-x=4/7

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Solution for 5/7x^2-x=4/7 equation: 


x in (-oo:+oo)

(5/7)*x^2-x = 4/7 // - 4/7

(5/7)*x^2-x-(4/7) = 0

(5/7)*x^2-x-4/7 = 0

5/7*x^2-x-4/7 = 0

DELTA = (-1)^2-(-4/7*5/7*4)

DELTA = 129/49

DELTA > 0

x = ((129/49)^(1/2)+1)/(5/7*2) or x = (1-(129/49)^(1/2))/(5/7*2)

x = 7/10*((129/49)^(1/2)+1) or x = 7/10*(1-(129/49)^(1/2))

x in { 7/10*(1-(129/49)^(1/2)), 7/10*((129/49)^(1/2)+1) }

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